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As far as I can make out he's proposing to measuring longitude by measuring the the apparent position of the Moon at "local midnight".

15 degrees of latitude is one hour of difference in local time, during which the moon will move by 33 arc minutes (about one Moon apparent diameter). So that's the kind of accuracy we're talking about.

"It's the statue, man, The Statue."

by Migeru (migeru at eurotrib dot com) on Wed Apr 25th, 2007 at 06:17:52 PM EST
[ Parent ]
So  about accurate enough so you could be standing in England or France and not know the difference from your observations.

Any idiot can face a crisis - it's day to day living that wears you out.
by ceebs (ceebs (at) eurotrib (dot) com) on Wed Apr 25th, 2007 at 06:28:50 PM EST
[ Parent ]
He does say
An instrument capable of sidereal measurement to 1 arc minute would result in an accuracy of 7.5 nautical miles at 45ºN
The problem is that he's assuming he can locate an object 31 arc minutes across to 1 arc-minute accuracy.

It is one thing to determine the distance between two (pointlike) starts to 1 arc minute by naked eye (with the aid of his instrument) but quite another to locate the moon to that accuracy.

"It's the statue, man, The Statue."

by Migeru (migeru at eurotrib dot com) on Wed Apr 25th, 2007 at 06:36:03 PM EST
[ Parent ]

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