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This is nonsense. If the 13 trillion aren't really 13 trillion, then why bother making such a commitment in the first place?

You're arguing like a gambler who puts his house on the poker table but tells everyone it's just for show, as it's practically impossible that he could lose this round.



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$E(X_t|F_s) = X_s,\quad t > s$

by martingale on Fri Jun 5th, 2009 at 05:19:18 AM EST
[ Parent ]
It's for show. It's a way of saying 'Yes, we're good for this. No crisis is so big we can't afford to handle it.'

Which means people will keep buying the IOUs. For now.

by ThatBritGuy (thatbritguy (at) googlemail.com) on Fri Jun 5th, 2009 at 07:17:01 AM EST
[ Parent ]
The problem with this crisis are the IOUs in the first place. Too many people have issued IOUs, and can't repay them. Now the "solution" has been to issue further taxpayer IOUs to cover these bad IOUs. The lie is that these taxpayer funded IOUs are somehow fake or worthless.

Ask youself who is stupider: investors and creditors who accept worthless pretend IOUs to cover known bad IOUs, or taxpayers who believe that the IOUs their government has issued in their name are fake and will never be paid out when asked.

You can't have it both ways, either you "solve" the problem with real IOUs, or you issue fake IOUs and "solve" nothing, since everyone knows they aren't worth anything.

The point of real IOUs is that there is real risk attached to them. It doesn't do to hope that things will work out without anybody requiring payment.

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$E(X_t|F_s) = X_s,\quad t > s$

by martingale on Fri Jun 5th, 2009 at 08:22:47 AM EST
[ Parent ]
As you know, the betting strategy with the highest probability of winning in the end is "double or nothing".

It is, on average, a losing strategy, but if you're going to gamble...

The brainless should not be in banking. — Willem Buitler

by Migeru (migeru at eurotrib dot com) on Sun Jun 7th, 2009 at 05:22:49 AM EST
[ Parent ]
the expectation of gain, is like other strategies, exactly zero. What you presumably mean is that you get a (n-1)/n chance of "winning" 1, by betting n, with n being an exponential of 2 (and a 1/n chance of losing n)

So the question, as expected, is whether you win before you run out of liquidity...

In the long run, we're all dead. John Maynard Keynes

by Jerome a Paris (etg@eurotrib.com) on Sun Jun 7th, 2009 at 08:24:40 AM EST
[ Parent ]
You're both right. It's true that the probability of winning 1 more than the initial amount in your pocket is 1 (ie certain), and in fact it is certain that this will occur within a finite number of bets. Moreover, by changing the monetary units, or by increasing the rate of growth of the bets, even bigger amounts can be won per bet, so the probability is maximal but the strategy is of course not unique.

However, the expected number of bets to achieve the outcome is infinite, since the strategy is nonintegrable, and while one game might(!) let you win 1 with certainty, in repeated games you will run out of money, or if you have infinite funds, you will fail to achieve any strictly positive rate of winnings in the long run (and depending on how you compute the rate of winnings, you could fail to achieve any finite negative rate of winnings either, ie the losses can't be usefully limited).

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$E(X_t|F_s) = X_s,\quad t > s$

by martingale on Mon Jun 8th, 2009 at 05:12:13 AM EST
[ Parent ]

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