Gusts and sustained don't matter, it is absolutely essential to get an accurate prediction of mean annual wind speed. There is nothing better than setting up your own anemometer on the site, but one can begin to extrapolate from airport, government and university data. For certain there's a group which has already studied NM winds, and likely state gov reports publically available. AWEA site has the NREL map of wind speeds.
You have to check whether NM has net metering, and what the permitting situation is. 100 ft elevation is likely too low "in town" as you need to get above turbulence.
AWEA has a site dedicated to answering questions about small wind. Two residential companies i can recommend are Bergey Windpower and Southwest Windpower. There you'll be able to see what you need for 100,000 kwh per year. Off the top of my head, that sounds impossible for a residential turbine. "Life shrinks or expands in proportion to one's courage." - Anaïs Nin
Wind Energy FAQ
How Can I Calculate the Amount of Power Available at a Given Wind Speed?
Contributed By Eric Eggleston, 5 February 1998
Because air has mass and it moves to form wind, it has kinetic energy. You may remember from science class that:
kinetic energy (joules) = 0.5 x m x V2
where: m = mass (kg) (1 kg = 2.2 pounds) V = velocity (meters/second) (meter = 3.281 feet = 39.37 inches)
Usually, we're more interested in power (which changes moment to moment) than energy. Since energy = power x time and density is a more convenient way to express the mass of flowing air, the kinetic energy equation can be converted into a flow equation:
Power in the area swept by the wind turbine rotor:
P = 0.5 x rho x A x V3
where: P = power in watts (746 watts = 1 hp) (1,000 watts = 1 kilowatt) rho = air density (about 1.225 kg/m3 at sea level, less higher up) A = rotor swept area, exposed to the wind (m2) V = wind speed in meters/sec (20 mph = 9 m/s) (mph/2.24 = m/s)
This yields the power in a free flowing stream of wind. Of course, it is impossible to extract all the power from the wind because some flow must be maintained through the rotor (otherwise a brick wall would be a 100% efficient wind power extractor). So, we need to include some additional terms to get a practical equation for a wind turbine.
Wind Turbine Power:
P = 0.5 x rho x A x Cp x V3 x Ng x Nb
where: P = power in watts (746 watts = 1 hp) (1,000 watts = 1 kilowatt) rho = air density (about 1.225 kg/m3 at sea level, less higher up) A = rotor swept area, exposed to the wind (m2) Cp = Coefficient of performance (.59 {Betz limit} is the maximum thoretically possible, .35 for a good design) V = wind speed in meters/sec (20 mph = 9 m/s) Ng = generator efficiency (50% for car alternator, 80% or possibly more for a permanent magnet generator or grid-connected induction generator) Nb = gearbox/bearings efficiency (depends, could be as high as 95% if good)
If there is any single equation that the beginning wind enthusiast should memorize, this is it. "Life shrinks or expands in proportion to one's courage." - Anaïs Nin
While putting up a residential sized wind turbine is do-able I would prefer to do this as a money-making business. 100,000 kwh - and I know that means annual production - is what is required to make the "math" work, ROI, income stream, & all that.
BTW, I need to be concerned about peak wind speed as I'd just as soon not have the tower crashing down on one of the structures 'round here, the turbine ripping off the top of the tower and flying away, etc., etc.
Being a Designated Cynic isn't merely my job, it's my passion.
:-)
H'mm. Let me try and recast my question.
My requirements, at the money I can afford to throw at the situation, are larger than the normal "residential" market and way too small for the serious players. Before I put a lot of personal time - of which I have little free - I need to find out if there is a reputable manufacturer with a reliable product in my (admittedly minuscule) market niche.
As you can see, NM basically has strong ridgelines, and little else. This is why certain areas already have windparks, as in the Guadalupe Mtns. Hardly anywhere has over 500 w/m2. (Compare to Scotland with much over 700w/m2)
This map indicates that New Mexico has wind resources consistent with utility-scale production. The largest contiguous area of good-to-excellent resource is in central New Mexico between Albuquerque and Clovis. Other notable areas of good-to-excellent resource are located near the Guadalupe Mountains in southern New Mexico, near Tucumcari, and in the northeastern part of the state near the Colorado and Oklahoma borders.
No, you don't need to be concerned about peak wind speed, unless you have strong hurricane winds a few hours a day, in which case you don't live where you live. Certified turbine tower combinations are designed to survive 150 mph winds, and be able to return to power production after 120.
I already gave you two very reputable manufacturers of different scale, and local dealerships, which you didn't acknowledge. If you need a larger turbine, the strongest turbine in the world comes from Northern Power Systems, and operates well in polar regions or at microwave repeater stations high in the Canadian Rockies with maintenance necessary only when the repeater station is visited. But they are expensive of course.
Being a Designated Cynic doesn't absolve you from doing your own homework. And how does "getting the math to work" work if you need to keep investing in larger and larger swept area to get your 100,000 kwh per year? "Life shrinks or expands in proportion to one's courage." - Anaïs Nin
