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Text Solution

100 mA200 mA20 mA10 mA

Answer :

CSolution :

Given, e = 200`sqrt 2` sin 100t <br> and C = 1`mu`F <br> `underset(rms)(E)` = 200 V <br> `underset(C )(X)` = 1/`omega`C = 1/`1 xx 10^(-6) xx 100` = `10^(4)Omega` <br> `underset(rms)(i)` = `underset(rms)(E)`/`underset(C )(X)` `adr` `underset(rms)(i)` =`200 / 10^(4)` = `2 xx 10^(-2)` A = 20 mA