# Line slope calculator 5x+3y=39

**Straight line given by points A[3; 8] and B[6; 3]**

## Calculation:

**Slope-intercept form of line:**y = -1.6667x+13

**Canonical form of the line equation:**5x+3y-39 = 0

**Parametric form of the line equation:**

x = 3t+3

y = -5t+8 ; t ∈ R

**Slope:**m = -1.6667

**Slope angle of line: φ =**-59°2'10″ = -1.0304 rad

**X intercept:**x

_{0}= 7.8

**Y intercept:**y

_{0}= q = 13

**Distance line from the origin:**d

_{0}= 6.6884

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; -5)

**Normal vector: n =**(5; 3)

**Midpoint of the segment AB: M =**[4.5; 5.5]

**Perpendicular Bisector equation:**3x-5y+14 = 0

**Vector OA = (3; 8) ; |OA| = 8.544**

**Vector OB = (6; 3) ; |OB| = 6.7082**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 42°52'44″ = 0.7484 rad**